x^2+11x-494=0

Solution for x^2+11x-494=0 equation:

x^2+11x-494=0

a = 1; b = 11; c = -494;
Δ = b2-4ac
Δ = 112-4·1·(-494)
Δ = 2097
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2097}=\sqrt{9*233}=\sqrt{9}*\sqrt{233}=3\sqrt{233}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3\sqrt{233}}{2*1}=\frac{-11-3\sqrt{233}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3\sqrt{233}}{2*1}=\frac{-11+3\sqrt{233}}{2}
$